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Mathematics 22 Online
OpenStudy (anonymous):

recent question - help me ?

OpenStudy (anonymous):

OpenStudy (anonymous):

this one is -40

OpenStudy (anonymous):

-36??

OpenStudy (anonymous):

OpenStudy (anonymous):

\[f(0)=6\] \[g(6)=6^3=216\]

OpenStudy (anonymous):

whooops mrjoselon is right and i am wrong. help2 is -36 not -40 sorry

OpenStudy (anonymous):

is ok. i need helpme3 now.

OpenStudy (anonymous):

helpme3 answer is 216

OpenStudy (anonymous):

216 agreed

OpenStudy (anonymous):

new one :) <3

OpenStudy (anonymous):

its 2

OpenStudy (anonymous):

you appear to have posted this same exact question about 40 times by now

OpenStudy (anonymous):

seriously right? it's not that hard...

OpenStudy (anonymous):

\[g(30)=\sqrt{30-5}=\sqrt{25}=5\] \[f(5)=2\times 5-8=10-8=2\] so answer is 2

OpenStudy (anonymous):

OpenStudy (anonymous):

nothing that hard when you know how to do it.

OpenStudy (anonymous):

thanks so much satellit73 ur great <3 but i really need help /:

OpenStudy (anonymous):

4x^4 + 1

OpenStudy (anonymous):

\[f\circ g(x)=f(g(x))=f(x^4)=4x^4+1\]

OpenStudy (anonymous):

OpenStudy (anonymous):

\[f\circ g(x)=f(g(x))=f(x^3)=-4x^3+7\]

OpenStudy (anonymous):

OpenStudy (anonymous):

<333

OpenStudy (anonymous):

you must be done by now yes?

OpenStudy (anonymous):

no /: i have 10 questions. im only on 7

OpenStudy (anonymous):

or at least have the idea of what to do . first get rid of the little circle \[f\circ g(x)=f(g(x))\] then replace g(x) by whatever it is, in this case \[f(x^2)\] and the replace the x in f(x) by x^2 to get \[9x^2-5\]

OpenStudy (anonymous):

OpenStudy (anonymous):

ok first find \[f(0)\] what do you get?

OpenStudy (anonymous):

1 :) ?

OpenStudy (anonymous):

right! then find \[g(1)\] and you get...

OpenStudy (anonymous):

1 ? :D

OpenStudy (anonymous):

you win. that is the answer. next...

OpenStudy (anonymous):

OpenStudy (anonymous):

yay! haha. so how do we do this one?

OpenStudy (anonymous):

ah now we have to think. but not too much

OpenStudy (anonymous):

:( you can help me?

OpenStudy (anonymous):

you have \[f(x)=h(g(x))=h(8x^4-3)\] yes?

OpenStudy (anonymous):

yes :) <3

OpenStudy (anonymous):

and also you know that \[h(8x^4-3)=(8x^4-3)^2\] yes?

OpenStudy (anonymous):

yes :D

OpenStudy (anonymous):

so what did h say do do to the input?

OpenStudy (anonymous):

it said to cube it! in other words... \[h(x)=x^3\]

OpenStudy (anonymous):

okay what do we put in for x?

OpenStudy (anonymous):

oops cube, not square. i made a typo above. so first you do g which says \[g(x)=8x^4-3\] and then you do h which says cube the result

OpenStudy (anonymous):

she still has no idea what to do dude

OpenStudy (anonymous):

i don't understand what you mean "what do we put in for x?"

OpenStudy (anonymous):

no no i miss understood continue on. im kinda understanding.

OpenStudy (anonymous):

i guess you have to put in \[x^3\]

OpenStudy (anonymous):

im sorry im not so bright .. gsh . but im trying

OpenStudy (anonymous):

this plato looks like a drag

OpenStudy (anonymous):

its the worse :(

OpenStudy (anonymous):

y'all done yet?

OpenStudy (anonymous):

no hunn i need two more questions to answer before 1230 or ima fail :(

OpenStudy (anonymous):

okay post emup

OpenStudy (anonymous):

well lets do them before 12:15 then

OpenStudy (anonymous):

OpenStudy (anonymous):

cause you sure as hell don't want to do this again!

OpenStudy (anonymous):

we just did this one. \[h(x)=x^3\]

OpenStudy (anonymous):

so one more....

OpenStudy (anonymous):

no i need a number is not letting me type out letters

OpenStudy (anonymous):

i got it! last one

OpenStudy (anonymous):

sorry you are going to have to type x^3 in there some how

OpenStudy (anonymous):

OpenStudy (anonymous):

here we go. ready? what is \[f(6)\]?

OpenStudy (anonymous):

6!

OpenStudy (anonymous):

right. now guess what we need? we need \[g(6)\]

OpenStudy (anonymous):

216 ?

OpenStudy (anonymous):

you found the sound. answer is 216

OpenStudy (anonymous):

that is it done finished stick a fork in it. yes?

OpenStudy (anonymous):

YAY! i fninished the sectioon <3 thanks so much hunn i hope u can help me in the near future again ur extremly smart :) thanks again.

OpenStudy (anonymous):

you are quite welcome. now forget math for a while and go back to fear and faith

OpenStudy (anonymous):

lol i might be back later on today to finish some more <3 thanks hun ill ttyl

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