Question

Activity title: solving problems for uniformly accelerated rectilinear motion
learning target: to calculate displacement,velocity,acceleration and time using the four kinematic equations.

1. A french high-velocity train accelerated uniformly from 250km/hr to 300 km/hr as it sped through a distance of 50 km.finds its acceleration.

Answer 1

its hard

Answer 2

275ms^-2 i gave u the formula

Answer 3

what is the formula?

Answer 4

first tell me is ti right?

Answer 5

v^2 - u^2 = 2as
s is the dist

Answer 6

some 1 answer like this v² = u² + 2as
where v = final velocity
u = initial velocity
s = distance

here v = 300 km/h = 300,000 m/3600 s = 250/3 m/s
u = 250 km/h = 250,000 m/3600s = 625/9 m/s
s = 50 km = 50000 m

Answer 7

?

Answer 8

i feel confused but i remembered the prof on the blackboard write 3600s something from the other question..

Answer 9

ishaan your formula is correct how can i use that?

Answer 10

hey kingkos, I have already sent u the full solution!!!!!!

Answer 11

where?

Answer 12

u keep posting the same question repeatedly and do not wait for answer.......

here it is again....

above equation can be rearranged as follows:
v² - u²
------ = a
2 s

( 250 )^2 ( 625 )^2 m^2
(------ ) - (------) -------
( 3 ) ( 9 ) s^2
----------------------------------- = a
2 * 50000 m

62500 390625 m^2
------ - -------- ------
9 81 s^2
-------------------------- = a
100000 m

562,500 - 390,625 m^2
------------------ ------
81 s^2
------------------------- = a
100,000 m

171,875 1 m^2
------- * ---------- --------- = a
81 100,000 s^2 * m

Answer 13

thx

Answer 14

171,875 m
--------- ----- = a
8,100,000 s^2

so a = 0.02 m/s^2

Answer 15

i will study this your answer is interesting thank you sir

Answer 16

yehey

Answer 17

how can i be fast to get the conversion ur so fast i need it when the test come