find the roots of 2(x-3)^2-11=0 to two decimal places by isolating (x-3)^2 then taking the square root of both sides

Question

anonymous · Answer

To isolate the (x-3)^2, add 11 to both sides and then divide by 2.
$$(x-3)^{2}=11/2$$
Now take the square root of both sides.  FInally add 3 to both sides.

Remember, when you take the square root, you will have plus/minus in front of the radical.

anonymous · Answer

x= (11/2)^1/2 +3
now use calculator

anonymous · Answer

x=5.35

anonymous · Answer

OMG! you rock!

anonymous · Answer

The problem statement asks for "the roots".  What is the value of the other root?

anonymous · Answer

it should be$$\pm\sqrt{11/2}+3$$
You need both the positive and negative radical.

Plug both into calculator.

anonymous · Answer

Correct,$$-\sqrt{11/2}+3 = 0.654792  $$

anonymous · Answer

THANKS! :D