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OpenStudy (bahrom7893):
ln7^x = ln12
xln7 = ln12
x = ln12/ln7 = 1.94
OpenStudy (anonymous):
now is when you need the calculator!
OpenStudy (bahrom7893):
wait it's 1.27
OpenStudy (bahrom7893):
NOT 1.94..
OpenStudy (anonymous):
Oh boy! How do u use the cal?
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OpenStudy (bahrom7893):
windows calculator SUCKS!
OpenStudy (anonymous):
you solve
\[b^x=A\] for x in one step only.
\[b^x=A \iff x=\frac{\log(A)}{\log(b)}\]
OpenStudy (anonymous):
this is sometimes called "change of base formula" and if you remember i just showed you how to cheat on
\[\log_b(A)\] by computing
\[\log(A)\div \log(b)\]
OpenStudy (anonymous):
this is exactly the same. you are trying to find
\[\log_7(12)\] but of course you do not have log base 7 on your calculator. so instead you take out calculator and type in
\[\log(A)\div \log(7)\] and out pops answer
OpenStudy (anonymous):
dumb question, what is A?
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OpenStudy (anonymous):
ok the general form is
\[b^x=A\] and you want x. you have
\[7^x=12\] so what is A?
OpenStudy (anonymous):
12?
OpenStudy (anonymous):
yes. so you solve by typing in
\[\log(12)\div \log(7)\] in english, "the log of the total divided by the log of the base"
OpenStudy (anonymous):
bahrom solved using
\[x=\ln(12) \div \ln(7)\] you can check you get the same answer it makes no difference which log you use
OpenStudy (anonymous):
yes!! I am excited:)
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