7^x=12
ln7^x = ln12 xln7 = ln12 x = ln12/ln7 = 1.94
now is when you need the calculator!
wait it's 1.27
NOT 1.94..
Oh boy! How do u use the cal?
windows calculator SUCKS!
you solve \[b^x=A\] for x in one step only. \[b^x=A \iff x=\frac{\log(A)}{\log(b)}\]
this is sometimes called "change of base formula" and if you remember i just showed you how to cheat on \[\log_b(A)\] by computing \[\log(A)\div \log(b)\]
this is exactly the same. you are trying to find \[\log_7(12)\] but of course you do not have log base 7 on your calculator. so instead you take out calculator and type in \[\log(A)\div \log(7)\] and out pops answer
dumb question, what is A?
ok the general form is \[b^x=A\] and you want x. you have \[7^x=12\] so what is A?
12?
yes. so you solve by typing in \[\log(12)\div \log(7)\] in english, "the log of the total divided by the log of the base"
bahrom solved using \[x=\ln(12) \div \ln(7)\] you can check you get the same answer it makes no difference which log you use
yes!! I am excited:)
Thank you so much!! God bless u:)
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