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Mathematics 19 Online
OpenStudy (anonymous):

7^x=12

OpenStudy (bahrom7893):

ln7^x = ln12 xln7 = ln12 x = ln12/ln7 = 1.94

OpenStudy (anonymous):

now is when you need the calculator!

OpenStudy (bahrom7893):

wait it's 1.27

OpenStudy (bahrom7893):

NOT 1.94..

OpenStudy (anonymous):

Oh boy! How do u use the cal?

OpenStudy (bahrom7893):

windows calculator SUCKS!

OpenStudy (anonymous):

you solve \[b^x=A\] for x in one step only. \[b^x=A \iff x=\frac{\log(A)}{\log(b)}\]

OpenStudy (anonymous):

this is sometimes called "change of base formula" and if you remember i just showed you how to cheat on \[\log_b(A)\] by computing \[\log(A)\div \log(b)\]

OpenStudy (anonymous):

this is exactly the same. you are trying to find \[\log_7(12)\] but of course you do not have log base 7 on your calculator. so instead you take out calculator and type in \[\log(A)\div \log(7)\] and out pops answer

OpenStudy (anonymous):

dumb question, what is A?

OpenStudy (anonymous):

ok the general form is \[b^x=A\] and you want x. you have \[7^x=12\] so what is A?

OpenStudy (anonymous):

12?

OpenStudy (anonymous):

yes. so you solve by typing in \[\log(12)\div \log(7)\] in english, "the log of the total divided by the log of the base"

OpenStudy (anonymous):

bahrom solved using \[x=\ln(12) \div \ln(7)\] you can check you get the same answer it makes no difference which log you use

OpenStudy (anonymous):

yes!! I am excited:)

OpenStudy (anonymous):

Thank you so much!! God bless u:)

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