Question

factor the trinomial:

(3x+2)^2 + 8 (3x+2) + 12

Answer 1

1) Simplify
2) Find roots of (3x+2)^2 + 8 (3x+2) + 12 = 0
3) Answer is 9(x-1st root)(x-2nd root)

Answer 2

1st step is not necessary.

Answer 3

Answer is (3x+4) (3x+8)

Answer 4

Yes, it can also be given in form 9(x+4/3)(x+8/3)

Answer 5

The roots are -4/3 and -8/3

Answer 6

9(x+4/3)(x+8/3) = 3*(x+4/3)*3(x+8/3) = (3x+4) (3x+8)

Answer 7

(3x+2)^2 + 8 (3x+2) + 12
Let

\[u=3x+2\]

\[u^2+8u+12=(u+2)(u+6)\]

\[=(3x+2+2)(3x+2+6)=(3x+4)(3x+8)\]