Question

Divide the complex numbers:
(6-1) over (5+4i)

Answer 1

is it 6-i? as numerator ?

Answer 2

I meant (6-i), yes

Answer 3

sry , \[6-i \div5+4i = 6-i \times5-4i/9\]

Answer 4

can u sove it here on ?

Answer 5

\[\frac{6-i}{5+4i}=\frac{6-i}{5+4i}\frac{5-4i}{5-4i}=\frac{(6-i)(5-4i)}{5^2-5\cdot4i+5\cdot4i-(4i)^2}\]

\[=\frac{(6-i)(5-4i)}{25-16(-1)}=\frac{(6-i)(5-4i)}{25+16}=\frac{(6-i)(5-4i)}{41}=\cdots\]

Answer 6

its right ...Zarkon.

Answer 7

in the end you should get

\[\frac{26}{41}-\frac{29}{41}i\]

Answer 8

any other problem , if u have ...aria ?