Question

1 - x
---
x + 1
---------
2 - x - 1
-----
x

Answer 1

\[\frac{1-\frac{x}{x+1}}{2-\frac{x-1}{x}}\]

Answer 2

multiply top and bottom by
\[x(x+1)\] to clear the factions

Answer 3

that is correct

Answer 4

so numerator will be
\[(1-\frac{x}{x+1})\times x(x+1)\]
\[=x(x+1)-x^2\]
denominator will be
\[(2-\frac{x-1}{x})\times x(x+1)\]
\[2x(x+1)-(x-1)(x+1)\]
giving
\[\frac{x(x+1)-x^2}{2x(x+1)-(x-1)(x+1)}\]

Answer 5

then multiply out and combine like terms in numerator and denominator

Answer 6

numerator is
\[x\]
denominator is
\[2x^2+2x-(x^2-1)=x^2+2x+1\] if my algebra is correct.

Answer 7

looks good

Answer 8

why thank you!

Answer 9

dont let it go to your head