Question

If i(t)=4u(t) and e(t)=8u(t)-8u(t-2).What is the value of i-2 ? (see attachment)

Answer 1

The answer choices are;
1. i2=u(t-2)
2. i2=-u(t)+u(t-2)
3. i2=3u(t)+u(t-2)

Answer 2

Oh, your question asked for \[i-2\]which I assumed to be \[i(t)-2\]So here's the correct solution. This time I won't reverse the currents.
From the right loop,
\[-e(t)=6i_2+2(i_2-i_1)\]
\[-et(t)=8i_2-2i_1\]
\[8i_2=2i_1 -e(t)\]
\[8i_2=8u(t)-(8u(t)-8u(t-2))\]
\[i_2=u(t-2)\]
There you go.

Answer 3

Sorry that was my misprint.Thank you for you time.It was very helpful.