Question

Differentiate implicitly, cos^2x+cos^2y=cos(2x+2y)

Answer 1

\[-[\sin(2x)+\sin(2y)]\div 2=1/2 \sin(2x+2y)\]

Answer 2

^thats rubbish lol

Answer 3

anything wrong?

Answer 4

yeh all of it

Answer 5

you didnt find the derivative

Answer 6

also the expression they have is \[\cos^2 x +\cos^2 y = \cos(2x+2y)\]

Answer 7

you thought the ^2 , mean 2x

Answer 8

differentiate both sides\[-\sin(2x) -\sin(2y) \frac{dy}{dx} = - ( 2 + 2\frac{dy}{dx}) \sin(2x+2y) \]

Answer 9

also you integrated the terms :|, so many mistakes lol

Answer 10

and the integral of cos is not - sin , lol what did u do

Answer 11

rearrange my thing above to get dy/dx

Answer 12

\[\frac{\text{dy}}{\text{dx}}=-\frac{\sin (x) \cos (x)-\sin (2 x+2 y)}{\sin (y) \cos (y)-\sin (2 x+2 y)} \]

Answer 13

sorry you are right elecengineer