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Solve for (dy/dx) at the given points x^2-y^4=x^3+y^5 at (x,y) = (-1,1)
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2x -4y^3 dy/dx = 3x^2 +5y^4 dy/dx
\[2x - 4y^3\frac{dy}{dx} = 3x^2 +5y^4 \frac{dy}{dx}\]
u do the rest
Many thanks elecengineer! Thats exactly the type of help I was looking for. I just wasn't very sure on how to to begin the problem.
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