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Mathematics 18 Online
OpenStudy (anonymous):

new plato questions (help me?)

OpenStudy (anonymous):

OpenStudy (anonymous):

Define some variables and set up some equalities representing the situation.

OpenStudy (anonymous):

l is length. w is width. a = area. l+w = 18 a = l*w a = 80, so 80 = l*w

OpenStudy (anonymous):

sorry heres this one, i did that one alreay

OpenStudy (anonymous):

If you have two equations and two unknown variables, the standard method is to pick a variable and an equation and then isolate the variable in that equation. Once you've done that, substitute for that variable in the second equation and solve. This should give you a simple numeric answer for 1 variable. If you substitute for that variable in either of the original equations, you can solve for the second variable.

OpenStudy (anonymous):

i dont get it :(

OpenStudy (anonymous):

Okay, so applying that method to this second problem... the variables are a and b. "one integer is 5 less than another" so a = b-5 "the product of the two integers is 24" so a*b = 24

OpenStudy (anonymous):

4*6?

OpenStudy (anonymous):

Okay, so start by just picking one of your equation and solve it for one of the variables. For example: a = b-5 This one is already how we want it written. a is isolated on one side of the variable. Now substitute b-5 for a in the other equation. a*b = 24 and a = b-5, so (b-5)*b = 24

OpenStudy (anonymous):

So (b-5)*b = 24 b^2 - 5b =24 b^2 - 5b -24 = 0 Use the quadratic formula to solve for b. Plug the answer into b in the equation a=b-5 to get the answer for a.

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