Question

The shortest side of a polygon of area 196 sq. in. is 4 in. long. Find the area of a similar polygon whose shortest side is 8 in. long.

Answer 1

THEOREM Areas of Similar Polygons
The ratio of the areas of two similar polygons is equal to the square of the ratio of the corresponding sides.

Answer 2

Answer is that area of 2nd polygon is 784 in^2

Answer 3

The scale factor of these polygons is 4:8 or 1:2
So ratio of areas is \[1^2/2^2=1:4\]
Then, if 1st polygons area is 196, 2nd polygons area will be \[4 \times 196=784\]