Mathematics
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OpenStudy (anonymous):
CAN SOMEONE PLEASE HELP ME WIH PRODUCTS OF RADICALS?
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OpenStudy (anonymous):
heres the question
OpenStudy (anonymous):
i can try
OpenStudy (anonymous):
\[\sqrt{6} * \sqrt{8}\]
OpenStudy (anonymous):
\[\sqrt{6*8}\]
OpenStudy (anonymous):
\[\sqrt{48}\]
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OpenStudy (anonymous):
mane why you yellin? :P
OpenStudy (anonymous):
sorry, just needed help asap.
OpenStudy (anonymous):
ready for next question?
OpenStudy (anonymous):
\[4\sqrt{3}\]
OpenStudy (anonymous):
Next question
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OpenStudy (anonymous):
okay show me how to do it though :) please.\[\sqrt{2}*\sqrt{10}*\sqrt{5}\]
OpenStudy (anonymous):
10
OpenStudy (anonymous):
\[\sqrt{100}\]
OpenStudy (anonymous):
it was. that was my explanation. i put 10 above it
OpenStudy (anonymous):
okay what about.....
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OpenStudy (anonymous):
\[\sqrt{8}*\sqrt{5}\]
OpenStudy (anonymous):
\[\sqrt{8*5}=\sqrt{40}=2\sqrt{10}\]
OpenStudy (anonymous):
why \[2\sqrt{10}\]
OpenStudy (anonymous):
To simplify it
OpenStudy (anonymous):
sqrt. of 4 is 2. You can take that out
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OpenStudy (anonymous):
because you are pulling out a 4 from the radical and the square root of 4 is 2
OpenStudy (anonymous):
soo what would be \[3\sqrt{8}\]
OpenStudy (anonymous):
6root 2
OpenStudy (anonymous):
Yes
OpenStudy (anonymous):
Same logic
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OpenStudy (anonymous):
Pull out all the factors which are perfect squares by writing their square-roots outside the radical.
OpenStudy (anonymous):
Understood meli11?
OpenStudy (anonymous):
not one of my options
OpenStudy (anonymous):
soo no
OpenStudy (anonymous):
What are the options?
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OpenStudy (anonymous):
what are your options?
OpenStudy (anonymous):
I don't see you typing your options
OpenStudy (anonymous):
i think i giot the hang of it.
OpenStudy (anonymous):
Great! By the way, in which grade are you studying?