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Mathematics 20 Online
OpenStudy (anonymous):

CAN SOMEONE PLEASE HELP ME WIH PRODUCTS OF RADICALS?

OpenStudy (anonymous):

heres the question

OpenStudy (anonymous):

i can try

OpenStudy (anonymous):

\[\sqrt{6} * \sqrt{8}\]

OpenStudy (anonymous):

\[\sqrt{6*8}\]

OpenStudy (anonymous):

\[\sqrt{48}\]

OpenStudy (anonymous):

mane why you yellin? :P

OpenStudy (anonymous):

sorry, just needed help asap.

OpenStudy (anonymous):

ready for next question?

OpenStudy (anonymous):

\[4\sqrt{3}\]

OpenStudy (anonymous):

Next question

OpenStudy (anonymous):

okay show me how to do it though :) please.\[\sqrt{2}*\sqrt{10}*\sqrt{5}\]

OpenStudy (anonymous):

10

OpenStudy (anonymous):

\[\sqrt{100}\]

OpenStudy (anonymous):

it was. that was my explanation. i put 10 above it

OpenStudy (anonymous):

okay what about.....

OpenStudy (anonymous):

\[\sqrt{8}*\sqrt{5}\]

OpenStudy (anonymous):

\[\sqrt{8*5}=\sqrt{40}=2\sqrt{10}\]

OpenStudy (anonymous):

why \[2\sqrt{10}\]

OpenStudy (anonymous):

To simplify it

OpenStudy (anonymous):

sqrt. of 4 is 2. You can take that out

OpenStudy (anonymous):

because you are pulling out a 4 from the radical and the square root of 4 is 2

OpenStudy (anonymous):

soo what would be \[3\sqrt{8}\]

OpenStudy (anonymous):

6root 2

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

Same logic

OpenStudy (anonymous):

Pull out all the factors which are perfect squares by writing their square-roots outside the radical.

OpenStudy (anonymous):

Understood meli11?

OpenStudy (anonymous):

not one of my options

OpenStudy (anonymous):

soo no

OpenStudy (anonymous):

What are the options?

OpenStudy (anonymous):

what are your options?

OpenStudy (anonymous):

I don't see you typing your options

OpenStudy (anonymous):

i think i giot the hang of it.

OpenStudy (anonymous):

Great! By the way, in which grade are you studying?

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