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Hello everyone, I have a question. I am supposed to put this into standard form, (2+i)/(3i). And to do so I have to multiply by the conjugate, how do i find the conjugate?
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Multiply by (2-i)/(2-i)
Both the top and the bottom?
Don't overthink it. Just multiply it.
\[\frac{2+i}{3i}=\frac{2}{3i}+\frac{i}{3i}=\frac{2}{3i}*\frac{i}{i}+\frac{1}{3}=\frac{2i}{3i^2}+\frac{1}{3}\] \[\frac{2i}{3(-1)}+\frac{1}{3}\]
\[=\frac{-2}{3}i+\frac{1}{3}\]
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Thank you. I made a mistake in my computation and you helped me catch it. Thanks :)
np
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