Question

Find an equation of the line that satisfies the given conditions.
x-intercept 5; y-intercept −10

Answer 1

y=mx+b is the equation for a line
x intercept is (5,0)
y intercept is (0,-10)

so we know two points on the line we can find m (the slope)

slope=m=\[\frac{ \Delta y}{\Delta x}=\frac{0-(-10)}{5-0}=\frac{10}{5}=2\]

so we have y=2x+b

now using either point we can find b (the y-intercept)

we have (x=5,y=0)

so we have

0=2*5+b
0=10+b
-10=b

so the equation of the line that have intercepts (5,0) and (0,-10) is
y=2x+(-10)

or

you can say

y=2x-10

Answer 2

what about this:
Find an equation of the line that satisfies the given conditions.
Through (2, 9); parallel to the line passing through
(3, 7) and (−1, 3)

Answer 3

find slope of the line containing points (3,7) and (-1,3)
parallel lines have the same slope

so whatever you find that slope to be use it for
y=mx+b (then you can b by pluggin' in (2,9) )
let me know what you get i will check k

Answer 4

im doin it wrong do you mind walkin me through it

Answer 5

\[m=\frac{7-3}{3-(-1)}=\frac{4}{3+1}=\frac{4}{4}=1\]
did you get this for slope?

Answer 6

yes

Answer 7

so we have y=1x+b
we know a point on the line (2,9)
9=1*2+b
solve for b
9=2+b
9-2=b
7=b

so the equation of the line going through (2,9) and is parallel to the line containing points (3,7) and (-1,3) is y=1x+7 or you can simply write y=x+7

Answer 8

thanks so much