One spinner has 48 equal sections and 6 are blue. A second spinner has 72 equal sections and 9 are blue. What is the probability that blue will be spun on both spinners?
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OpenStudy (anonymous):
\[\frac{6}{48}\times \frac{9}{72}\]
OpenStudy (anonymous):
how did you set this up?
OpenStudy (anonymous):
well you have 6 blues out of 48 so ratio is
\[\frac{6}{48}\] yes? that is the probability that you get a blue on the first spinner
OpenStudy (anonymous):
likewise the probability you get a blue on the second spinner is
\[\frac{9}{72}\]
OpenStudy (anonymous):
ohhh
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OpenStudy (anonymous):
and now you want them BOTH to be blue. assuming they are independent, meaning that the outcome on the first spinner has no effect on the second , then the probability that they both happen is the product of the probabilites
OpenStudy (anonymous):
this reduces way down. i believe the answer is
\[\frac{1}{64}\]
OpenStudy (anonymous):
thank you :)
OpenStudy (anonymous):
yw
myininaya (myininaya):
satellite when will i be guru?
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OpenStudy (anonymous):
same day i am sensei
myininaya (myininaya):
it says you are guru
you lie
what number do i need to reach to be guru