Why would one use the square root property of equality instead of factoring to solve quadratic equations?

Question

anonymous · Answer

some quadratic equations cannot be factored

anonymous · Answer

i meant factored easily. What I mean is factoring works in a very tiny percentage of quadratic equations. in most equations it is not evident what the factors of a particular equation are.

anonymous · Answer

example would be 
$$x^2+6x-1=0$$ which does not factor over integers. so you would say 
$$x^2+6x=1$$
$$(x+3)^2=1+9=10$$
$$x+3=\pm\sqrt{10}$$ 
$$x=-3\pm\sqrt{10}$$ because it does not factor using integers you use square root property

anonymous · Answer

Thank you both so much. You were a big help. Now it makes sense