Question

solve for variable x in the following equation pls someone:
2/x-4 + 1/x+4 = 5x/x^2-16
the solution x is

Answer 1

can someone help me plse:
solve for variable x in the following equation pls someone:
2/x-4 + 1/x+4 = 5x/x^2-16
the solution x is

Answer 2

x is 2. you want the steps?

Answer 3

yes pls that would be great satellite

Answer 4

Can you help with this one satellite pls
x+1/x+6 = x-1/x=3

Answer 5

idea is to add on the left hand side. you get
\[\frac{2}{x-4}+\frac{1}{x+4}=\frac{2(x+4)+1(x-4)}{x^2-16}\]
\[=\frac{3x+4}{x^2-16}\] and the right hand side is
\[\frac{5x}{x^2-16}\] so set
\[3x+4=5x\] and solve for x via
\[3x+4=5x\]
\[2x=4\]
\[x=2\]

Answer 6

correction satellite the equation is:
x+1/x+6 = x-1/x+3

Answer 7

that is what i thought. maybe this time we "cross multiply" to get
\[(x+1)(x+3)=(x+6)(x-1)\]
\[x^2+4x+3=x^2+5x-6\]
\[4x+3=5x-6\]
\[3+6=5x-4x\]
\[9=x\]

Answer 8

thanks satellite you are very smart have a good night