Question

help someone plse:
2-a-4/a+3 = a^2-2/a+3

Answer 1

(2-a-4)/(a+3) =(a^2-2)/(a+3)

is this what you are asking jazi1?

Answer 2

yes but nothing is in parenthese

Answer 3

oh so it just looks like that on the question paper?
because it could mean 2-a -(4/a+3) or [(2-a-4)/a] +3 and so on

Answer 4

no it is 2 - a-4/a+3 = a^2-2/a+3
the 2 and - sign is in line with the bar that separates the left and right equation

Answer 5

right then you would solve using the cross method

Answer 6

coul you show me how plse

Answer 7

a-4 a^2 -2
2- ---- = ------- ------ 2(a+3) - (a-4) = a^2 -2
a+3 a+3

2a+6-a+4 = a^2 -2
a+10=a^2 -2
a^2 -a -12 =0
1+/- radical ( 1+48) 1+/- radical 49 1 +/- 7
a_1,_2 = ------------------- = ---------------- = --------
2 2 2

a_1 = 8/2 =4
a_2 = -6/2 =-3

a_1 =4
a_2 =-3

Answer 8

\[2-\frac{a-4}{a+3}=\frac{a^2-2}{a+3}\]

Add the terms on the left side of the equals so as to get everything over (a+3) and then you can get rid of the (a+3)'s on both sides.