Prove {2 * sin (theta) * cos(theta) - cos(theta)}/{1 - sin(theta) + sin^2(theta) - cos^2(theta)} = cot(theta)
madhur.. u wanna work on this problem
yaa
do u know the formula for sin2theta have u tried tht?
these things can be tricky, often a good idea to look for clues in the question. In this case, the right hand side is cot or 1/Tan = Cos/Sin so if you could somehow get the left hand side to be cos/sin you would be home.
I've got a Idea ... U can take cos common out of the numerator and convert 1 into sin^2 + cos^2
I'm talking about the 1 in denominator
cos^2 gets cancel and then u take sin common and u get ur answer :)
Him is tht right? I think It is
Looks pretty good to me...
that looks absolutely good so just looking at the bottom: 1=sin^2x+cos^2x then use that cos^2x-cos^2x=0 so you have on bottom sin^2x+sin^2x-sinx=2sin^2x-sinx=sinx(2sinx-1) and on top you have cosx(2sinx-1)
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