Find the solutions to the equation (check all that apply) x2+14x+48=0. a.x=-2 b.x=1/2 c.x=2 d.x=-1/2 e.x=3 f.x=3/2
try plugging each value into the function until you find one that makes it true
the equations's the same as the last problem, but the choices are different...are you sure about that equation?
I just need help and the equation is wrog its 4x2+4x+1=0
a little trick on factoring...some forms afe nicer than others. \[(ax+b)^{2}=a^{2}x^{2}+2abx +b^{2}\] since your first term is a perfect square and your last term is a perfect square, it's a good candidate.
if it works, then a=2 and b=1. so the question is, does 2ab=4? if so, then your factored form would be \[(ax+b)^{2}\]where a=2 and b=1
2(2)(1)=4...you're in luck
so, your factored form is \[(2x+1)^{2}=(2x+1)(2x+1)=0\] so now solve the same as last problem.
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