Question

Six alphabets (A, B, C, D, E, F) are randomly arranged in a line.

a. How many different arrangements are possible if the vowels (i.e. A and E) are next to each other?

b. What is the probability that the vowels (i.e. A and E) are next to each other?

Answer 1

5! x 2!

Answer 2

hmmm probably but maybe not

Answer 3

@him i believe you, but at first glance it looks like maybe you are assuming that it goes AE, or am i mistaken? oh i am mistaken. sorry

Answer 4

no prob sat

Answer 5

wait min

Answer 6

you have two groups (AE) (BCDF)

Answer 7

that means 2! x 2! x 4! arrangements

Answer 8

sorry elecengg

Answer 9

u have one group of AE and 5 other independent elements

Answer 10

ahh yes