When solving a rational inequality, I know I'm supposed to solve the numerator for zero, and the denominator for any number that will result in an undefined value, but what if after solving it, I don't have a denominator to work with?
give example please
The rational inequality is 5/(x+2)>5/x+2/3x
What you wanto to do in this case, is first add the two faractions on the right hand side, to do that you will need a common denominator
Then once you have added those fractions move that term to the left had side of the >
My final result was 0>2x+34, so x>-17.
it makes no difference in that case because it not less than or equal
if you have something like \[\frac{x}{x+3} \le 1 \]
yep, just remeber that whenever you divide you have to flip the inequality sign
then you need to exclude the denominator
What exactly do you mean by exclude?
When solving other problems I usually get a polynomial fraction for example (w^2-16)/(w-3). From this, I can tell that 3 can't be a solution of the inequality because it would yield an undefined result. I also know that by having the numerator equal to 0, I can the points I will use as a reference in this particular example it would be w^2-16=0, or w^2=16, which w could be +-4. In the original case I did not have a denominator to work, does that mean that I should only use -17 as a reference point?
Join our real-time social learning platform and learn together with your friends!