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Mathematics 19 Online
OpenStudy (anonymous):

I need help with this problem, I do not know what it wants. The area of a rectangular athletic field is represented by the expression 48x^4 +32x^3-72x square meters. Write an algebraic expression to represent one possible set of dimensions (in the sense "length times width") of the athletic field. Include correct units with your solution.

OpenStudy (anonymous):

first you need to realize that that the area is the product of length and width. so if you can factorize the above expression you will get the product of two expression. one bracket will be the length and the other will be the width

OpenStudy (anonymous):

one solution could be taking out a common factor...(8x)(6x^3 + 4x^2 -9)...

OpenStudy (anonymous):

I can get that far. What do I do after that? If possible just explain how to do the next step, see if I can figure it out. (Thank you for your help).

OpenStudy (anonymous):

uhm, that is the answer. they want an algebraic expression for the width and length. you have two algebraic expressions, one is the width and the other is the length.

OpenStudy (anonymous):

Oh, ok. I was thinking they wanted me to work it out. So what about the square meters, is it still meters^2? Or how would you write that?

OpenStudy (anonymous):

area is square meters. but individual dimensions are just meters. its like saying you multiply two numbers that are measured in meters and now you get a number that is square meters. eg. width=7m, length=8m, area = (7m)(8m)=56 square m

OpenStudy (anonymous):

Oh, ok. I was thinking they wanted me to work it out. So what about the square meters, is it still meters^2? Or how would you write that?

OpenStudy (anonymous):

Thank you for your help!

OpenStudy (anonymous):

uw

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