Question

Find the area under the curve from y= cosx/ pi +sinx from 0 to infiniti

Answer 1

What math you take?

Answer 2

Calculus :/

Answer 3

Your a Junior?

Answer 4

Integrate form 0 to infinity

Answer 5

\[\frac{\text{Cos}[x]}{\pi +\text{Sin}[x]}\]
did I write you function correctly?

Answer 6

senior. imranmeah can you help me out a little more buddy? not exactly im stuck between 0, 2.76, .693, and .079 :/ please help! kay thanks :)

Answer 7

did imranmeah91 wrote your function correctly?

Answer 8

Yes, I am wondering if I copies the equation correctly above?

Answer 9

yeahhh :)

Answer 10

its right so far...

Answer 11

\[\int_0^{\infty } \frac{\cos (x)}{\sin (x)+\pi } \, dx\]
Simple U-Sub from here
u=Sin(x)+pi
du= cos(x) dx

Plug back in

Answer 12

\[\int_0^{\infty } \frac{1}{u} \, du\]

Answer 13

speak for yourself. :x this is like a whole different language to me :/

Answer 14

How much have you learned in regard to integration?

Answer 15

Welp to be honest, not much. This is complete jargon. That's why I need your help! Kay thanks :)

Answer 16

ln(sin(x)+pi)|[0,inf]
ln(sin(inf)+pi)-ln(pi)
sin(inf) isnt defined its always going back to +1---->-1

to reason it out i would say since ln is only positive it would look like ln(1+pi)-ln(pi)

.2763

Answer 17

or twice that sin from o to pi is 2 and if it never goes negative then you would double that, but this question has something wrong because sin(inf)is not defines

in calc 1 the lim as x--->inf of sin(x) is not defined because it doesnt hit anything