Question

Calculus problem

Answer 1

sup
might know it

Answer 2

The limit as h approaches 0 of abs value (x+h) -abs value of x divided by h at x=3 is...

Answer 3

1

Answer 4

Explanation?

Answer 5

It diverges, (goes to infinity)

Answer 6

\[\lim_{h \to 0}\frac{|3 + h| - |3|}{h} = \lim_{h \to 0}\frac{3 + h - 3}{h} = \lim_{h \to 0}\frac{h}{h} = \lim_{h \to 0}\ 1 = 1.\]Because for small h (|h| < 3) |3 + h| > 0, so |3 + h| = 3 + h.

Answer 7

Thanks!