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Mathematics 21 Online
OpenStudy (anonymous):

2x+5y=10

OpenStudy (anonymous):

determine the slope and the y-intercept

OpenStudy (anonymous):

The standard equation of a line is y = mx+c, where m is the slope and c is the y-intercept Making the equation in this form we get,\[y = \frac{-2}{5}\times x+2\] Hence, slope = -2/5 and intercept = 2

OpenStudy (id21):

\[y=\frac{-2x}{5}+\frac{10}{5}\] \[y=\frac{-1}{5}x+2\] slope= -1/5 y intercept=2

OpenStudy (anonymous):

thank you I have a few more

OpenStudy (anonymous):

\[15x ^{2}+29x+12\]

OpenStudy (anonymous):

\[15x^2+29x+12=0\] \[15x^2+20x+9x+12=0\] \[5x(3x+4)+3(3x+4)=0\] \[(5x+3)(3x+4)=0\] \[x=\frac{-5}{3}\text{ or }x=\frac{-4}{3}\]

OpenStudy (anonymous):

thank you that made it more understandable.

OpenStudy (anonymous):

\[(a+7)^{2}+5(a+7)-6\]

OpenStudy (anonymous):

my instructor got the answer (a+13)(a+6)

OpenStudy (anonymous):

\[(a+7)^2+6(a+7)−(a+7)−6=0\] \[(a+2)(a+7+6)−1(a+7+6)=0\] \[(a+7−1)(a+7+6)=0\] Simplify now to get the answer

OpenStudy (anonymous):

My bad it was I used (a+2) instead of (a+7) :) Corrected it now!

OpenStudy (anonymous):

\[\sqrt{7/48xy ^{2}}\]

OpenStudy (anonymous):

\[\sqrt{\frac{7}{4^2\times3xy^2}}=\frac{1}{4y}\sqrt{\frac{7}{3x}}\]

OpenStudy (anonymous):

the answer is suppose to be \[\sqrt{21x/12xy}\]

OpenStudy (anonymous):

But I cant figure it out

OpenStudy (anonymous):

What do you need to do with the expression? Anything that describes the question?

OpenStudy (anonymous):

no thats it

OpenStudy (anonymous):

Ohk, thats how you need to do it :) \[\sqrt{\frac{7}{4^2\times3xy^2}}\] Multiply numerator and denominator both by 3x to get \[\sqrt{\frac{7\times3x}{4^2\times(3x)^2y^2}}=\frac{1}{12xy}\sqrt{21x}\]

OpenStudy (anonymous):

\[2x ^{3}-6x ^{2}-4x-12\]

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