2x+5y=10
determine the slope and the y-intercept
The standard equation of a line is y = mx+c, where m is the slope and c is the y-intercept Making the equation in this form we get,\[y = \frac{-2}{5}\times x+2\] Hence, slope = -2/5 and intercept = 2
\[y=\frac{-2x}{5}+\frac{10}{5}\] \[y=\frac{-1}{5}x+2\] slope= -1/5 y intercept=2
thank you I have a few more
\[15x ^{2}+29x+12\]
\[15x^2+29x+12=0\] \[15x^2+20x+9x+12=0\] \[5x(3x+4)+3(3x+4)=0\] \[(5x+3)(3x+4)=0\] \[x=\frac{-5}{3}\text{ or }x=\frac{-4}{3}\]
thank you that made it more understandable.
\[(a+7)^{2}+5(a+7)-6\]
my instructor got the answer (a+13)(a+6)
\[(a+7)^2+6(a+7)−(a+7)−6=0\] \[(a+2)(a+7+6)−1(a+7+6)=0\] \[(a+7−1)(a+7+6)=0\] Simplify now to get the answer
My bad it was I used (a+2) instead of (a+7) :) Corrected it now!
\[\sqrt{7/48xy ^{2}}\]
\[\sqrt{\frac{7}{4^2\times3xy^2}}=\frac{1}{4y}\sqrt{\frac{7}{3x}}\]
the answer is suppose to be \[\sqrt{21x/12xy}\]
But I cant figure it out
What do you need to do with the expression? Anything that describes the question?
no thats it
Ohk, thats how you need to do it :) \[\sqrt{\frac{7}{4^2\times3xy^2}}\] Multiply numerator and denominator both by 3x to get \[\sqrt{\frac{7\times3x}{4^2\times(3x)^2y^2}}=\frac{1}{12xy}\sqrt{21x}\]
\[2x ^{3}-6x ^{2}-4x-12\]
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