Mathematics
11 Online
OpenStudy (anonymous):
Find the number of all combinations of 8 objects a, b, c, d, e, f, g, and h taken 7 at a time.
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OpenStudy (anonymous):
Are you familiar with the nCr notation?
OpenStudy (anonymous):
noooo we are supposed to use permutations i believe
OpenStudy (anonymous):
No, this is not a permutation problem.
OpenStudy (anonymous):
This is a combination problem.
OpenStudy (anonymous):
ohhhhh yes you ar correct. can you help me with it?
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OpenStudy (anonymous):
Are you familiar with nCr and what it means?
OpenStudy (anonymous):
noo i am not
OpenStudy (anonymous):
Ok. Well it is a notation to solve this exact problem.
OpenStudy (anonymous):
do you know the answer?
OpenStudy (anonymous):
nCr is an expression which tells you how many different combinations of r different things you can make from a pool of n things.
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OpenStudy (anonymous):
Does that make sense?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
ok, so in this case how big is our pool?
OpenStudy (anonymous):
8?
OpenStudy (anonymous):
Correct. And how many things will we be taking from the pool to make our combinations?
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OpenStudy (anonymous):
7?
OpenStudy (anonymous):
Correct.
So the answer to this problem is 8C7
OpenStudy (anonymous):
But that doesn't help much cause they want a real number.
OpenStudy (anonymous):
So now, let me give you the formula for nCr, and you can use it to find 8C7
OpenStudy (anonymous):
okay! great!
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OpenStudy (anonymous):
\[nCr \equiv \frac{n!}{r!(n-r)!} \]
OpenStudy (anonymous):
So can you use that to figure out what 8C7 is?
OpenStudy (anonymous):
282240?
OpenStudy (anonymous):
is this the correct answer?
OpenStudy (anonymous):
\[\frac{8!}{7!(8-7)!} = \frac{8!}{7!1!} = \frac{8!}{7!}\]
With me so far?
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OpenStudy (anonymous):
ohhhhh yess!!!! i put it all together! now i see!
OpenStudy (anonymous):
So what is the answer?
OpenStudy (anonymous):
8?
OpenStudy (anonymous):
Correct.
OpenStudy (anonymous):
you are so helpful!!!
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OpenStudy (anonymous):
i have another question! can you help me?
OpenStudy (anonymous):
How many ways are there to seat 4 people in a 9-passenger automobile? Assume that some times there will be no one in the driver's seat.