Question

x^3+2x^2=16x+32.
solve polynomial equation by factoring then using zero product principle. what is the solution set?

Answer 1

\[x ^{3}+2x ^{2}=16x+32\]

Answer 2

\[x ^{2}(x+2)=16(x+2)\]divide both sides by (x+2) getting:
\[x ^{2}=16\]
\[x=\pm 4\]

Answer 3

I believe they work:
-64+32=-64+32
64+32=64+32

Answer 4

Did you follow that lar0213

Answer 5

I didn't show an intermediate step
\[x ^{2}=16\]\[\sqrt{x ^{2}}=\sqrt{16}\]\[x=\pm4\]
That should make it more understandable.
Good luck with your studies.