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I need help with simplifying logarithms log[4]{log[3](log[2] 8)}
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like this?: \[\log_4(\log_3(\log_2(8)))\]
yes, except the 8 is not in it's own parenthesis
lets look at the inside part first: \[\log_2(8) = \log_2(2^{3}) = 3\] so now we have: \[\log_4(\log_3(3))\]
\[\log_3(3) = 1\] so now we have: \[\log_4(1)\] and the log of 1 equals 0 no matter what the base, so the final answer is 0 :)
is there anything you need me to explain in more detail?
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