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how do you solve: ∛12v/π for the variable v?
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is v inside the radical?
yeah it is
everything is under the radical
ok so you've got the cube root of 12v/pi
and you need to find out what v is
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is this just equal to 0?
it's equal to d. i didn't see that.
ah, ok
so you can split the fraction inside the radical into a radical in the numerator and a radical in the denom.
cube root 12v / cube root of pi
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sorry, can't type it out properly
\sqrt[3]{12v} / \sqrt[3] {pi}
latex doesn't work for me here..
after you do that, multiply both sides by cube root of pi (denominator)
then you will need to get rid of the radical on both sides by cubing each side
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which will leave you with 12v on the left
then you can divide everything by 12 and isolate the v
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