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Mathematics 24 Online
OpenStudy (anonymous):

Find the indicate term for each geometric series described

OpenStudy (anonymous):

\[Find : a _{1}\]\[s _{n}=33\]\[a _{n}=48\]\[r=-2\]

OpenStudy (anonymous):

the key a1 =3

OpenStudy (anonymous):

u sure u got question right?

OpenStudy (anonymous):

how many gs\s are there?

OpenStudy (anonymous):

yes,I sure

OpenStudy (anonymous):

how many geometric series are we talking about?

OpenStudy (anonymous):

that all I get from question

OpenStudy (anonymous):

I don't know

OpenStudy (anonymous):

the formular:\[s _{n}=\frac{a _{1}(1-r^n)}{1-r}\]

OpenStudy (anonymous):

ok i made a mistake - i used n = 2 - sorry

OpenStudy (anonymous):

try again

OpenStudy (anonymous):

I can't do it , because without n I can't solve

OpenStudy (anonymous):

be back

OpenStudy (anonymous):

it geting late I go sleepp ,if u fid answer , fust write it , I will check back tomorrow ,TY

OpenStudy (anonymous):

33 = a1(1 - (-2)^n) / 1-(-2) 33 = a1(1 - (-2)^n) / 3............(1) also 48 = a1*(-2)^(n- 1)...........(2) equations (1) and (2) need to be solved simultaneously

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

from (1) 99 = a1 (1 - (-2)^2)........(3) from (2) 48 = a1 ((-2)^n * (-2)^-1) = a1 ((-2)^2 * -1/2)) 48 = (-a1/2)(-2)^n (-2)^n = -96/a1 plug (-2)^n = -96/a1 into (3) 99 = a1 (1 +96/a1) 99 = a1 + 96 a1 = 99-96 = 3

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