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OpenStudy (anonymous):
Find the indicate term for each geometric series described
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OpenStudy (anonymous):
\[Find : a _{1}\]\[s _{n}=33\]\[a _{n}=48\]\[r=-2\]
OpenStudy (anonymous):
the key a1 =3
OpenStudy (anonymous):
u sure u got question right?
OpenStudy (anonymous):
how many gs\s are there?
OpenStudy (anonymous):
yes,I sure
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OpenStudy (anonymous):
how many geometric series are we talking about?
OpenStudy (anonymous):
that all I get from question
OpenStudy (anonymous):
I don't know
OpenStudy (anonymous):
the formular:\[s _{n}=\frac{a _{1}(1-r^n)}{1-r}\]
OpenStudy (anonymous):
ok i made a mistake - i used n = 2 - sorry
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OpenStudy (anonymous):
try again
OpenStudy (anonymous):
I can't do it , because without n I can't solve
OpenStudy (anonymous):
be back
OpenStudy (anonymous):
it geting late I go sleepp ,if u fid answer , fust write it , I will check back tomorrow ,TY
OpenStudy (anonymous):
33 = a1(1 - (-2)^n) / 1-(-2)
33 = a1(1 - (-2)^n) / 3............(1)
also 48 = a1*(-2)^(n- 1)...........(2)
equations (1) and (2) need to be solved simultaneously
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
from (1)
99 = a1 (1 - (-2)^2)........(3)
from (2)
48 = a1 ((-2)^n * (-2)^-1) = a1 ((-2)^2 * -1/2))
48 = (-a1/2)(-2)^n
(-2)^n = -96/a1
plug (-2)^n = -96/a1 into (3)
99 = a1 (1 +96/a1)
99 = a1 + 96
a1 = 99-96 = 3
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