can anyone do optimization?
a regular storage container with an open top is to have a volume of 10 m^3 The length of the base is twice the width material for the base is $10 and the sides $6. find the cost of the materials for the cheapest such container
Yay optimization, my fave topic!!
ok
we can do this step by step not too bad. put x = width so base is 2x and height h. volume is \[2x\times x\times h=10\] making \[h=\frac{10}{2x^2}=\frac{5}{x^2}\]
I already did it satellite! YAY!
that is wrong sorry
y?
satellite u were right actually I did it the same way on the link above and the answers were correct..
no it right then cost is \[C=10\times 2x\times x+4\times 6 \times x\times h \] \[C(x)=20x^2+24\times x \times \frac{5}{x^2}\] \[C(x)=20x^2+\frac{120}{x}\]
but if you are done i will quit
that was my equation too but thanks for the effort..
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