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Mathematics 22 Online
OpenStudy (anonymous):

can anyone do optimization?

OpenStudy (anonymous):

a regular storage container with an open top is to have a volume of 10 m^3 The length of the base is twice the width material for the base is $10 and the sides $6. find the cost of the materials for the cheapest such container

OpenStudy (bahrom7893):

Yay optimization, my fave topic!!

OpenStudy (bahrom7893):

http://www.twiddla.com/574903 Go there ill help u there

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

we can do this step by step not too bad. put x = width so base is 2x and height h. volume is \[2x\times x\times h=10\] making \[h=\frac{10}{2x^2}=\frac{5}{x^2}\]

OpenStudy (bahrom7893):

I already did it satellite! YAY!

OpenStudy (anonymous):

that is wrong sorry

OpenStudy (bahrom7893):

y?

OpenStudy (bahrom7893):

satellite u were right actually I did it the same way on the link above and the answers were correct..

OpenStudy (anonymous):

no it right then cost is \[C=10\times 2x\times x+4\times 6 \times x\times h \] \[C(x)=20x^2+24\times x \times \frac{5}{x^2}\] \[C(x)=20x^2+\frac{120}{x}\]

OpenStudy (anonymous):

but if you are done i will quit

OpenStudy (bahrom7893):

that was my equation too but thanks for the effort..

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