1.(3a4)3
That's enough. Please stop spamming.
For raising products to a power, you just multiply the power times the power of the factors: \[(a^bc)^d = a^{bd}c^d\]
so wait i have to distrubite the power of d??
You multiply the power of each of the factors in parens by the power the whole thing is raised to.
Give it a try and I'll check your answer.
ok so 3a^7
Nope. What is the exponent on any number that doesn't have a specific exponent?
well 3 does not have an exponent
It does though, You just don't have to write it. If it doesn't have an explicit exponent there is always an implied exponent of 1.
Also when you did the 'distribution' you appear to have added. You need to multiply.
so 3 exponent is one?
\[3 = 3^1\]
o ok
so it would be 3a^4+^3
no.
Look at this again. \[(cb^k)^d = c^db^{k\cdot d}\]
This is the same 'form' of problem as the one you are working on. In your problem what number corrisponds to the c in my example?
3
correct.
3^3a^4+^3
So since the 3 has an exponent of 1, when we multiply the exponent by the outer exponent (3) what will the final exponent be? Correct 3^3
So now for the a. What is the exponent of the a?
4
And we are raising a^4 to the 3rd power, so we need to multiply the exponent on the a by the exponent we are raising it to.
so what is a^(4*3)
so it would be a^12 power?
Correct. So the final answer is..
Simplify 3^3 to 27
ok so it w makes it to 27a^12
Correct. The take away message being.. If you have a number without an exponent assume the exponent is 1 AND If you raise a power to a power, multiply the exponents.
Now lets try your other one. \[(-2x3y)^4\]
ok so it means -6xy^4
\[(-2)^4 = 2^4 = 16\]
and \(3^4 = 81\)
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