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Simplify r^2a / r^2a-3. 2a and 2a-3 are radicals. Can you explain, also? Thanks!
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\[\frac {r^2\sqrt{2a}} {r^2\sqrt{a-3}}\] Yes?
Where do the radicals come from? Confused.. I don't think I learned this.
Is that the correct equation? Your post says r^2a but then says 2a is a radical which does not make sense.
\[r^{\sqrt{2a}}\] Or this?
Oh, I'm sorry. I meant 2a and 2a-3 are exponents. Apologies.
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\[\frac{r^{2a}}{ r^{2a-3}}\]
Is that right?
\[r ^{2a} / r ^{2a-3}\]
Yeah, that's right. (:
Apply rule for exponents a^p /a^q = a^(p-q).
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So it's r^(2a - 2a-3)?
yes, except it's 2a - (2a-3) which is different...
Oh, yeah. Sorry. Thank you very much. (:
u r welcome, if u don't like the equation editor, just use brackets to make things clear.
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