Question

Having a hard time solving radical equations with two radicals.
sqrt(4y+5)-sqrt(y-1)=3

Answer 1

(4y+5)-(y-1)=9
3y=3
y=1

Answer 2

I added sqrt(y-1) on both sides to get sqrt(4y+5)=3+sqrt(y-1) then squared both sides to get rid of the square roots to get 4y+5=(3+sqrty-1)squared but get lost from that point on.

Answer 3

If you square both sides of the equation, you get:

(4y+5)-(y-1)=9
4y+5-y+1=9
3y+6=9
3y=3
y=1

Answer 4

What's all this??? Everybody forgot how to square things?

mathisnofun started off right, continuing from there:

4y +5 = 9 + y -1 + 6 sqrt(y-1) (y'all call this FOIL, right?) -->

y-1 = 2sqrt (y-1) and square again -->

y^2 -6y + 5 = 0 --> (y-1)(y-5) --> y = 1 or 5.