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integral of e^x (sinx +cosx)
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on twidlla
Same thing you asked before, factorize it will give e^x * sinx + e^x * cosx . Think, what could have been the primitive of that? If you look again at the product rule, you see the same thing as before: e^x * sinx
Because the product rule to form derivatives is (u,v)' = u' * v + v' * u
Use that you receive before if integral of e^x(f(x)+f'(x)) = e^xf(x)+C, then integral of e^x (sinx +cosx)=e^xsinx+c
(you can use it because (sinx)'=cosx
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