what is meant by basis vectors?
basis vectors for a vector space (or subspace) of dimension 'n' is a set of n vectors whose span is the entire space. In other words, every vector in the space is a linear combination of the basis vectors. For example in the Cartesian plane (R^2), one basis could be the vectors (1,0), and (0,1). Any vector (x,y) = x(1,0) + y(0,1).
there is more to it than that, but this should at least provide an understanding.
Cartesian plane (R^2); by this you mean its like a disc right?
The xy-plane, what we usually graph on all the time.
Spanning is only one of the conditions.
A basis has two conditions. 1) It must span the vector space 2) It must be linearly independent
right right. i dont wish to confuse the masses though lol.
I like my bases to be orthogonal, lol.
Yes orthogonal bases are very nice.
With an orthogonal basis, if you want to express an arbitrary vector as a linear combination of the basis, all you need to do is compute some dot products.
On the other hand if the basis is not orthogonal you need to solve a system of equations.
@alchemista: what do you mean when you say that its linearly independent?
I like ab = a dot b + a wedge b (which can be generalized to multivectors).
guys i am a total newbie at this...i have no clue what terminologies you guys are using.. whats orthogonal basis?
xy plane, 1 unit on x, 1 unit on y is a basis. Or xyz in 3d. Perpendicular to each other.
@estudier: i understand what a dot b is... but whats a wedge b??
thanx estudier i get the idea what ortho basis is
In 3D it calculates a value equivalent to the cross product (which represents the area of the implicit //gram formed by the vectors a and b). Difference is cross only works in 3D, wedge works all dim and orientation is automatic.
A set of vectors are linearly independent if no vector in the set can be expressed as a linear combination of other vectors in the set. In other words you have the condition that for a set of vectors \[B=\{v_1, v_2, ..., v_n\}\] For coefficients \[\{a_1, a_2, ..., a_n\}\] If the set is linearly independent \[a_1v_1 + a_2v_2 + ... + a_nv_n = 0\] Only when a_i = 0 for all i=0 to n.
You can therefore think of a wedge b as a "patch" of oriented area (of any shape).
okay got it...can you provide a mathematical example of how wedge works? n thanx alchemista i undrstood what you said.
@estudier: what do tou mean by this:You can therefore think of a wedge b as a "patch" of oriented area (of any shape)?
*you
a wedge b = (a1b2 -a2b1)e12 + (a2b3-a3b2)e23 + (a3b1-a1b3)e31 (e_i is a (orthogonal) unit vector) The bracketed represent areas of //grams projected on to the basis planes. Compare with the formula for the cross.
hmm...except for the e_ij and a minus sign in the middle expression it looks just like a cross product. do i have it right?
Yes, these apparently minor differences are what allows the generalization. In fact there is an entire separate algebra for the wedge, the exterior algebra http://en.wikipedia.org/wiki/Exterior_algebra However, for many practical applications, this "outer product" works best when combined with the inner ("dot") product 8because ab is invertible).
okay thanx a lot
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