Question

Angelo rides his bicycle at an average rate of 14kph. Four hours later, Vance starts after Angelo on a motorcycle and overtakes him in 2 hours, what is Vance's rate?

Answer 1

Need to setup the problem first:
\[4(14) + 2(14) = 2x\]
The first 4(14) is what has been done prior to the second person starting.
The 2(14) is the time that Angelo is riding. The x is the speed of Angelo.
\[84 = 2x\]
\[x = 42\]
So the answer is 42 kph

Answer 2

I already came up with that answer but I dont know how to show it in equation. So, thanks for answering. THUMBS UP! :)

Answer 3

The distance Anglo and Vance ride is the same. Take the distance formula (d=v*t)for each and set them equal to each other.
d=distance
v=velocity
t=time
A=Angelo
V=Vance
so: v(A)*t(A)=v(V)*t(V) and solve for v(V)
v(A)*t(a)/t(V)= (14kph*6h)/2h=42kph

Answer 4

thank you! :)