Question

UPLOAD

Answer 1

1,2,16

Answer 2

mkuma36, how did you come up with 2 and 16?

Answer 3

a2 = 2 (a1)^2 = 2 * 1 * 1 =2

Answer 4

similarly a3 = 2(a2) ^3 = 2 (2) ^3 = 16

Answer 5

\[a_1 = 1, a_n=2(a_{n-1})^n\]
So, all you need to do is find \(a_1, a_2, a_3\)
\(a_1\) you already have. The sequence is recursive, so all you need to do is plug in n and \(a_{n-1}\).
\[a_1 =1\]
\[a_2 =2(a_{2-1})^2 = 2*1^2 = 2\]
\[a_3 =2(a_{3-1})^3 = 2*2^3 = 16\]

Answer 6

That is what my answer is.