Question

The current I in an electrical conductor varies inversley as the resistance R of the conductor. The current is 3 amperes when the resistance is 990ohms. What is the current when the resistance is 540ohms

Answer 1

for inverse relations xy = constant

here IR = V (here V is the constant)

I1R1 = 3 * 990 = 2970

So I2R2 also = 2970
I2* 540 = 2970
I2 = 2970/540
I2 = 5.5

so current in second case is 5.5 A

Answer 2

i = k/R
3 = k / 990
k = 2970
so
i = 2970 / R
when R = 540
current i = 2970 / 540
= 5.5 amperes