Question

solve the system by the substitution method

1/2x+1/3y= -1/2

1/2x+3y=15/2

the / make them fractions

Answer 1

Solve for y, then substitute the equations y = y, then solve for x

Answer 2

i would multiply first and second equation by 6 to get rid of annoying fractions first

Answer 3

multiply the two equations by six first of all

Answer 4

actually i lied

Answer 5

i would multiply first by 6, second by 2

Answer 6

get
\[3x+2y=-3\]
\[x+6y=15\]

Answer 7

then if you really want "substitution" write second one as
\[x=-6y+15\] and substitute into first equation to get
\[3(-6y+15)+2y=-3\]

Answer 8

\[-18y+45+2y=-3\]
\[-16y=-48\]
\[y=\frac{48}{16}=3\]

Answer 9

I guess nobody liked my method

Answer 10

then substitute back to get
\[x+6\times 3=15\][
\[x=18=15\]
\[x=-3\] and so your answer is (-3,3)

Answer 11

no i didn't like your method because fraction annoy me. but of course it makes no difference.

Answer 12

It's not a big deal. Just get it in terms of y, set the equations equal to each other, then cross multiply. It's actually less steps

Answer 13

ok write it out and see which one is easier to write