Evaluate the logarithm log[3]1/9
your job is to answer \[3^x=\frac{1}{9}\]
if you can answer this, you can solve the problem. otherwise you are stuck more or less
so is this possible?
x=-2 ;)
hipster will give you a hint. he (she) is fond of them...
hahahahahaa this is true. the answer lies on the interval (-1,1)
cough, 0. cough
actually if you have a calculator and wish to cheat (aka not think) i can show you how to get the answer. it is what i would do
do show us, satellite.
okay
got a calculator handy? we will find the answer (-2) quickly but first lets be clear. the answer is -2 because \[3^{-2}=\frac{1}{3^2}=\frac{1}{9}\] that is how you are "supposed to do it"
now get out your fancy ti 83 and type in \[\log(1\div 9)\div \log(3)\] and out will pop -2
thanks
so if you wish to cheat your teacher and find \[\log_4(\frac{1}{8})\] without saying \[4^{\frac{3}{2}}=8\] then just plug in \[\log(1\div8)\div \log(4)\] and out will pop \[\frac{3}{2}\] try it!
always happy to help some one do it the easy way.
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