Tom, wingspan and Harry started out on a journey of 100 km. Tom and Harry went by an automobile at the rate of 25km/hr, while wingspan walked at the rate of 5km/hr. After a certain distance, Harry got off and walked on at 5km/hr while Tom went back to wingspan and got him to the destination of the same time that Harry arrived. Find the number of hours required for the trip.

Question

anonymous · Answer

I am posting the following answer.Plz check whether it is right.

anonymous · Answer

Given, total distance=100km/hr
          auto's speed=25km/hr
          wingspan's speed=5km/hr
Let Harry get down from the auto after covering "x" km.
Remaining distance to be covered by Harry=(100-x)km
Time required=[100-x]/5

Suppose Tom meets wingspan after travelling for "y" kms.
Time covered=[y/25]hrs

Distance covered by wingspan=[x-y]km
Time required=[(x-y)/5] hr

Now, y/25=(x-y)/5
Or, 5y=25x-25y
Or, 25x=30y
Or, 5x=6y
Or, y=5x/6

Remaining  distance to be covered by Tom and wingspan=(100-y)km
Speed of the auto=25km/hr
Now, (100-x)/5=(600-x)/150

anonymous · Answer

In the earlier post, are all the equations correct?

anonymous · Answer

yes bhaiya u r right i m sure because each step is right here nothing is wrong

anonymous · Answer

Sad thing is that I am not going the exact answer.

anonymous · Answer

oh i see

anonymous · Answer

The time to complete the trip was 8 hours.
Refer to the attachment for a Mathematica solution.