the function D(x) models the cumulative number of death fom a diease x years after 1984. Estimate the year when there were 95000 deaths D(x)=3680^2+5079x+5873 There approximately 95000 deaths in the year ?
I think u meant: D(x)=3680x^2+5079x+5873
Now to find the approximate year when there were 95000 deaths: D(x)=3680^2+5079x+5873=95000
3680^2+5079x+5873=95000, solve for x
3680^2+5079x-89127=0
oh man I've been copying off your stuff so I'm also ending up with no x^2.. hold on
Now to find the approximate year when there were 95000 deaths: D(x)=3680x^2+5079x+5873=95000 3680x^2+5079x+5873=95000, solve for x 3680x^2+5079x-89127=0 http://www.wolframalpha.com/input/?i=Solve%283680x%5E2%2B5079x-89127%3D0%29
According to wolf, x1 = -5.7 and x2 = 4.3. Since we can't go back in time yet, our answer must be positive, therefore x = 4.3
There approximately 95000 deaths in the year 1984+x There approximately 95000 deaths in the year 1984 + 4.3 There approximately 95000 deaths in the year 1988.3 or roughly 1988
Thnak u for showing the steps, so that I can understand...
Please click on Good Answer if I helped, I really want to get to the next level, thanks =)!
I did and I always do for u, thanks....
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