use the quadratic formula to solve the equation

3x^2-7x-5=0

Question

use the quadratic formula to solve the equation

3x^2-7x-5=0

bahrom7893 · Answer

okay here's the quadratic:
first find the discriminant:
D = b^2-4ac

bahrom7893 · Answer

your equation is in the form:
ax^2+bx+c=0 where: a=3, b=-7,c=-5
D = b^2-4ac = (-7)^2-4*(3)*(-5) = 49 + 60 = 109

bahrom7893 · Answer

x1 = ( -b-sqrt(D) ) / (2a) = ( -(-7)- sqrt(109) )/(2*3)

bahrom7893 · Answer

x1 = (7-sqrt(109))/6
x2 is ( -b+sqrt(D) ) / (2a), so:
x2 = (7+sqrt(109))/6

bahrom7893 · Answer

just use a calculator to estimate those..

anonymous · Answer

I still need a little help..

bahrom7893 · Answer

with what?

anonymous · Answer

I do not have the proper tools to find the answer or else I have no clue what is going on in this problem

anonymous · Answer

to solve 
$$ax^2+bx+c=0$$ use 
$$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$$

anonymous · Answer

The formula for solutions of a quadratic ax^2 + bx +c = 0 is

$$\frac{-b \pm \sqrt{b^2-4ac}}{2a}$$

Plug the numbers into the formula and you get bahrom's result.