One day a friend visited my house and asked me the ages of my three sons. I replied that the product of my son's ages is 36 and the sum of their ages is equal to my house number. My friend who has a sharp and logical mind, requested me for another hint. I then told him that my eldest son has blue eyes! Following this he quickly told me their ages...wat is their ages?

Question

jhonyy9 · Answer

3 son's ages product equal 36 - this being abc =36 
the sum of their ages is house number 

- so this was very easy for your friend because he have know your house number what we not know and hence this is very difficile to calculate

anonymous · Answer

This problem is actually solvable.  First, let's make a list of all the ages that are possible and their sums.

36, 1, 1=38
18, 2, 1=21
12, 3, 1=16
9, 4, 1=14
9, 2, 2=13
6, 6, 1=13
6, 3, 2=11
4, 3, 3=10

Take a look at the second clue.  Let's say that the first option (36, 1, 1) were the actual answer.  Then the house number is 38.  But this would mean that the friend HAD ENOUGH INFORMATION to know what the ages were with just the first and second clue.  This means that the house number must be 13, because that's the only one that shows up twice in the table.  The final clue is that there is an OLDEST child, which means it cannot be 6, 6, 1.  

From this, we can conclude that the childrens' ages are 6, 3, and 2.