A sphere with center A has a surface area of 144 pi units squared. Find the volume of a sphere with center B whose radius is twice as large as the sphere with center A. What is the ratio of the volumes of the two spheres?
The volume of the sphere is 4/3 pi \[{4\over3} \pi r^3\] and this equals 144 pi for the first sphere. This gives:\[{4\over3}pir^3=144\pi\]
I Know The Radius Is 6.
Well then use the equation above for radius 12, if the second one is twice as large. I don't see the problem
I'm Trying to find the volume of Center A But i keep getting mixed up answers. I got 904.778 and then 150.8... I think I'm Doing Something Wrong o_o
Oh, I see. I am sorry, I misunderstood the problem.
Let's answer the ratio question first... (2r)^3 : r^3 = 8 :1
Yep
But I'm Confused About finding the volume of center A.. o_o
Well the surface is \[\pi r^2 \]
you can just solve this for r, it is\[\sqrt{144\over \pi}\]
i thought the radius was 6 though....
How do you know that?
144pi=4pi(r)^2 36=r^2 6=r
I am sorry, I the wrong person to help today. I forgot the pi under the root.
you are right
Thanks Anyway o_o
I'm having difficulties finding the volume of A...First, i got 904.778 and then when I did it again I received the answer 150.8...
u only have to find volume of B...
Vol (A) = 4/3 pi 6^3 Vol (B) = 8 * Vol (A)
Okay i figured it out: Volume of Center A: 904.778 Volume of Center B: 7238.229 So i divided those and I received the ratio of 1:8 (: Thanks for your guidance :D
I think it is OK to leave your answer as a multiple of pi.
OK, it's good to check your work but u are making it hard for yourself. You know it is 8:1 because (2r)^3 : r is 8 to 1.
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