Question

Find the general indefinite integral.http://www.webassign.net/cgi-bin/symimage.cgi?expr=int%20%5C%2814%20sqrt%28x%2A%2A3%29%20%2B%2013%20root3%28x%2A%2A2%29%5C%29%20dx

Answer 1

You can use the fact that sqrt is power 1/2 and cube root is power 1/3 and
rewrite the expression using rules for exponents.\[(x^3)^{1/2} + (x^2)^{1/3} = x^{3/2} + x^{2/3}\]

Then your integration is more straightforward to do.

Answer 2

can you t ell me the answer cuz i really cant do it this way,,

Answer 3

Do you know how to integrate x^2?

Answer 4

2x

Answer 5

That's differentiation. Integration is the reverse.

Answer 6

o x^2 would = to x^3/3?

Answer 7

Right:-)

Answer 8

so...im lost where am i intergrating?

Answer 9

Now, you can follow the exact same principle even though it's a fraction.

Answer 10

ok so 14x^(2/3) + 13 x^(2/3)

Answer 11

\[28/5(x ^{5/2} ) + 39/5 ( x ^{5/3})\]For the Answer....though I would recommend u to follow estudier ..U said u were in a Hurry .. thts Y I'm providing Answer : )

Answer 12

Do you want to see how to do it or you are happy just to receive the answer?

Answer 13

so it would be like this: (14x^(5/3)/(5/3) + (13x^(5/3)/(5/3) = 14(2/5)x^(5/2) + 13(3/5) x^(5/3) right?

Answer 14

no i get it..thanks to the both : )

Answer 15

Right, you up the exponent by 1 and divide by the new fraction for the integral part.
(Then your 14 and 13 are lust multiples as normal).