Question

ok i need huge help on this since the roots is 31...http://www.webassign.net/cgi-bin/symimage.cgi?expr=int_0%2A%2A4%20%28x%20-%202%29%2A%2A%2831%29%20dx

Answer 1

u=x-2
du= dx


\[\int u^{31} du\] from 2 to 6

Answer 2

no 4-0

Answer 3

4 to 0

Answer 4

I know since u= x-2 , we change the limits of integration

Answer 5

how?

Answer 6

where 6 comes from?

Answer 7

its 2 to -2

Answer 8

yes sorry it is -2 to 2

Answer 9

ok so now what i do?

Answer 10

u^31 -> 1/32 u^32 evaluate from -2 to 2

Answer 11

so this woild be: 1/32 (x-2)^32 correct? then i plug in the limits of 2 to -2.....(1/32 (2-2)^32)-(1/32(-2-2)^32=

Answer 12

0-1/32(-4)^32 right?

Answer 13

if you are going to change it back to x, leave that limit as they were 0 to 4

Answer 14

no im using the 2 to -2 as the limit..

Answer 15

so what would that be?

Answer 16

\[\frac{1}{32}u^{32}\]
\[\frac{1}{32}(2^{32}-(-2)^{32})\]

Answer 17

thats the answer?